[FIXED] get the exact XML, which is send to Soap Service

Issue

from our application we are calling a soap service like below

res = (CreateResponse) JAXBIntrospector.getValue(getWebServiceTemplate()
                    .marshalSendAndReceive(soapUrl, req, new headers(msgHeader)));

now i want to see the actual request xml which is send to the SOAP url.

soapUrl - target soap url

req - it is an object of a class CreateRequest

msgHeader - it is an object MsgHeader

Because, currently we are getting an error

ns0:MsgErrorCd Description="REQUEST STRUCTURE INVALID"

So the team , which maintains the SOAP service, need the input XML, Could you pls help me..

Solution

in the application.properties file, added the below lines, now the request xml is getting printed in the console.

logging.level.org.springframework.ws.server.MessageTracing.sent=DEBUG
logging.level.org.springframework.ws.client.MessageTracing.received=TRACE
logging.level.org.springframework.ws.server.MessageTracing.received=TRACE

Answered By - user_che_ban
Answer Checked By - Timothy Miller (JavaFixing Admin)