[FIXED] delete where all keys of a map are contained in a list in mongodb

Issue

I have this:

• A field which is a map where the keys are UUIDs and the value another object which is not relevant.
• A list of UUIDs that should be passed as parameter.

I want to:

delete from the collection all documents where all keys of the map are included in the list of UUIDs

The object:

@Document
public class MyClass
{
  private Map<UUID, anotherObject> myMap;
}

With derived queries I am not able to reach the UUID because has no name -> deleteByMyMap...

And with a query I know that there is a way to convert the map into an array ($expr and $objectToArray) but I do not know if it makes sense.

• Is there any way to do this?
• How can I access just the key of the map?

Solution

This could be also an answer:

db.collection.aggregate([
  {
    "$project": {
      "mapAsArray": {
        "$objectToArray": "$map"
      }
    }
  },
  {
    "$match": {
      "mapAsArray": {
        "$not": {
          "$elemMatch": {
            "k": {
              $nin: [
                "3478956c-3a01-404f-84e7-2a076e165215",
                "1e1d1efb-5bf9-48ac-93ca-4a2df5a9f7eb"
              ]
            }
          }
        }
      }
    }
  }
])

Here the mongoplayground

The map to spring-data-mongodb:

ProjectionOperation projectionOperation = project()
            .and(ObjectOperators.valueOf(myMap).toArray()).as(myMapToArray);

MatchOperation matchOperation = match(where(myMapToArray)
            .not()
            .elemMatch(where("k").nin(myList)));

AggregationResults<myObject> aggregate = mongoTemplate.aggregate(newAggregation(projectionOperation, matchOperation),
            myObject.class, myObject.class);

Answered By - Iker Aguayo
Answer Checked By - Clifford M. (JavaFixing Volunteer)