[FIXED] What am I missing in this recursion?

Issue

So I am trying to recursive print all the sum of odd digits in a number. Like the number 12345 would be 9 This code does not work, but I do not understand why.

public static int oddSum(int n){
            String nn = Integer.toString(n);
            if(nn.length()==1 && Integer.parseInt(nn)%2==1) {
                return Integer.parseInt(nn);
            } else if(nn.length()==1 && Integer.parseInt(nn)%2==0) {
                return 0;
            }
            if((int)nn.charAt(0)%2 == 1) {
                return oddSum(Integer.parseInt(nn.substring(1))+(int)nn.charAt(0));
            } else {
                return oddSum(Integer.parseInt(nn.substring(1)));
            }
        }

Solution

I kinda feel like this is a homework problem, but I'll bite.

I don't specifically know java, so I can't comment on the details of the code. But, if I'm reading it correctly, it seems like you're taking an integer, converting it to a string, stripping characters and returning them to integers to process? That seems convoluted.

What about this pseudo-code?

int oddSum(n)
{
    if (n < 10)
    {
        if (n%2 == 1)
            return n
        else
            return 0
    }
    return oddSum(n/10) + oddSum(n%10)
}

Answered By - Weylin Piegorsch
Answer Checked By - Cary Denson (JavaFixing Admin)