[FIXED] Updating a QuartzJob from the running job itself

Issue

The update of a QuartzJob within a spring boot application works while the job is not running (here or href="http://www.quartz-scheduler.org/documentation/quartz-2.3.0/cookbook/UpdateTrigger.html" rel="nofollow noreferrer">here). The spring variable spring.quartz.overwrite-existing-jobs: true is set.

However, when doing the same from within a running job the job keeps firing itself in an endless loop without taking into account the interval time (each few milliseconds it fires again). I even tried doing the same from within a TriggerListener but that doesn't change it.

As code example I would have nothing else but what is given in the second link above:

// retrieve the trigger
Trigger oldTrigger = sched.getTrigger(triggerKey("oldTrigger", "group1");

// obtain a builder that would produce the trigger
TriggerBuilder tb = oldTrigger.getTriggerBuilder();

// update the schedule associated with the builder, and build the new trigger
// (other builder methods could be called, to change the trigger in any desired way)
Trigger newTrigger = tb.withSchedule(simpleSchedule()
    .withIntervalInSeconds(10)
    .withRepeatCount(10)
    .build();

sched.rescheduleJob(oldTrigger.getKey(), newTrigger);

Did anyone try that from within a running job?

Solution

It works with the following trigger. It is the startAt which makes the difference. Without that the trigger fires immediately again.

Trigger trigger = newTrigger()
.withIdentity(triggerName, groupname)
.startAt(Date.from(LocalDateTime.now().plusSeconds(intervalInSeconds).atZone(ZoneId.systemDefault()).toInstant()))
.withSchedule(SimpleScheduleBuilder.simpleSchedule()
    .withIntervalInSeconds(intervalInSeconds)
    .repeatForever()
    .withMisfireHandlingInstructionIgnoreMisfires())
    .build();

Answered By - Kavau
Answer Checked By - David Marino (JavaFixing Volunteer)