[FIXED] How to get child properties from spring config

Issue

I have the following configuration:

external:
  shop-service:
    url: localhost:8080
    timeout: 5000
  pet-service:
    url: localhost:8081
    timeout: 10000
  user-service:
    url: localhost:8082
    timeout: 15000

I want to create some config library that will read these properties in every my service. In every service I can have different clients with different values of properties, but all of them have the same structure.

Any ways how I can get a map that will contain client name as a key and object that has url and timeout values, if I know only external property at the beginning and don't know exact client names?

Solution

this is my solution

private static final String BASE_PROPERTY = "clients.";
private static final String DELIMITER = ".";

private final org.springframework.core.env.Environment environment;

public Set<String> getClientNames() {
    return Arrays
        .stream(((EnumerablePropertySource<?>) ((ConfigurableEnvironment) environment)
            .getPropertySources()
            .stream()
            .filter(OriginTrackedMapPropertySource.class::isInstance)
            .findFirst()
            .orElseThrow(RuntimeException::new)).getPropertyNames())
        .filter(currentValue -> StringUtils.startsWith(currentValue, BASE_PROPERTY))
        .map(key -> StringUtils.substringBetween(key, DELIMITER, DELIMITER))
        .filter(Objects::nonNull)
        .collect(Collectors.toSet());
  }

Answered By - Alexey
Answer Checked By - Mildred Charles (JavaFixing Admin)