Issue
I am migrating my Quarkus project from the classic Hibernate ORM to Hibernate Reactive and I faced a problem with JSONB field mapping.
Here is the entity:
@Entity
@TypeDef(name = JsonTypes.JSON_BIN, typeClass = JsonBinaryType::class)
class MyEntity {
@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "myEntityIdGenerator")
@SequenceGenerator(name = "myEntityIdGenerator", sequenceName = "my_entity_id_seq", allocationSize = 10)
var id: Long? = null
// Usage of a plain JsonNode instead of a mapped class is intentional,
// as the app receives a request with raw JSON data and should store it without any processing
@Type(type = JsonTypes.JSON_BIN)
@NotNull
lateinit var jsonData: JsonNode
}
The project has the io.quarkiverse.hibernatetypes:quarkus-hibernate-types:0.2.0
dependency to handle JSON types.
This code worked fine with blocking Hibernate API, but when trying to persist a MyEntity
using the Hibernate Reactive, I get the following exception:
io.vertx.core.impl.NoStackTraceThrowable: Parameter at position[1] with class = [com.fasterxml.jackson.databind.node.ObjectNode] and value = [{"field1":"some value"}] can not be coerced to the expected class = [java.lang.Object] for encoding.
Is this a bug or custom types should be handled differently while using Hibernate Reactive?
Solution
Hibernate Types is not compatible with Hibernate Reactive.
But you have three options to map a Json with Hibenrnate Reactive:
- Use
io.vertx.core.json.JsonObject
- Map it as String and use a converter
- Create a UserType
1. JsonObject
Example with io.vertx.core.json.JsonObject
:
@Entity
private static class EntityWithJson {
...
private JsonObject jsonObj;
...
}
You can see a working example in the repository: JsonTypeTest
2. Using a converter
Example using a converter:
class EntityWithJson {
@Column(columnDefinition = "json")
@Convert(converter = StringToJson.class)
private String json;
...
}
@Converter
public class StringToJson implements AttributeConverter<String, JsonObject> {
@Override
public JsonObject convertToDatabaseColumn(String string) {
if (string == null) {
return null;
}
return new JsonObject(string);
}
@Override
public String convertToEntityAttribute(JsonObject dbData) {
if (dbData == null) {
return null;
}
return dbData.encodePrettily();
}
}
You can see a working example in the repository: JsonTypeTest
3. UserType
class EntityWithJson {
@Type(type="org.example.Json")
@Column(columnDefinition = "json")
private JsonObject jsonObj;
}
package org.example
public class Json implements UserType {
// ... Implementation left for brevity
}
You can see a working example in the repository: UserJsonTypeTest
Answered By - Davide D'Alto
Answer Checked By - Timothy Miller (JavaFixing Admin)