[FIXED] Storing digits of numbers in array

Issue

Hello fellow programmers ! I am a beginner with Java and i am looking for a method or a way maybe to store the digits of a 6 digit number entered by the user , in an int array. For example :- if the number is 675421. then i want to store the digits in an array like :-

int[] array = new int[6];
int number = 675421 
array[0] = 6;
array[1] = 7;
array[2] = 5; 
array[3] = 4;
array[4] = 2;
array[5] = 1;

I want to do so so that i can work with the array to maybe sort or change the order or numbers in array. Thanks!

Solution

Here you go,

String temp = Integer.toString(number);

int[] num = new int[temp.length()];

for (int i = 0; i < temp.length(); i++){
    num[i] = temp.charAt(i) - '0';
}

for (int i = 0; i < temp.length(); i++) {
    System.out.println(num[i]);
}

Edit, after comment

Here, First, you are converting to your number to a string. Then, take each char out of it(in the loop), subtract the ASCII value of 0 from each char to get the digit [ie, ASCII of 0 is 48, 1 is 49, ... ] (see ASCII table)

Answered By - Let'sRefactor
Answer Checked By - Gilberto Lyons (JavaFixing Admin)