Issue
I am using Java/Spring
I have XML like this:
<Transfer>
<Data>
...
</Data>
<Transfer>
and I just need to access to XML element "Data" for my model, like:
@JacksonXmlRootElement (localName = "Data")
Is it possible without additional wrapper class?
Solution
Friendly reminder to everyone: please don't mix-up JAXB with JacksonXML. All my problems were from there.
Just add an additional model, like in code below:
@Data
@JacksonXmlRootElement(localName = "Transfer")
public class WrapperClass{
@JacksonXmlProperty(localName="Data")
public MyClass myClas;
}
Answered By - Юрій
Answer Checked By - Cary Denson (JavaFixing Admin)