Issue
I am writing a spring-boot application which I want to deploy in a Weblogic 12C. The application exposes a SOAP Webservice. When running the application in standalone mode (spring-boot runs it by using an embedded tomcat) everything works fine and I can access the wsdl by
http://localhost:8081/ws/springbootwstest.wsdl
But if I deploy the application-war-file in the Weblogic, the Webservice is not available while the application itself is deployed successfully.
I cannot access the wsdl. I already followed the instructions on http://docs.spring.io/spring-boot/docs/1.2.2.BUILD-SNAPSHOT/reference/htmlsingle/#howto-weblogic but still same result.
All sources can be found here: https://github.com/iljahell/springbootwstest.git
java version "1.7.0_67"
spring-boot 1.2.0.RELEASE
Weblogic 12.1.3.0.0
Solution
I've solved this today after much frustration with weblogic 12c. Weblogic still requires you to define the spring ws message dispatcher servlet in your web.xml like this. Make sure you add the spring boot legacy dependency to your pom too.
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-legacy</artifactId>
<version>1.0.2.RELEASE</version>
</dependency>
Also, make sure you exclude the embedded tomcat from your spring boot ws dependency:
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-web-services</artifactId>
<exclusions>
<exclusion>
<groupId>org.apache.tomcat.embed</groupId>
<artifactId>tomcat-embed-websocket</artifactId>
</exclusion>
</exclusions>
</dependency>
Then
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>au.gov.qld.ambulance.mtaworkflow.webservices.SpringWsApplication</param-value>
</context-param>
<listener>
<listener-class>org.springframework.boot.legacy.context.web.SpringBootContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>spring-ws</servlet-name>
<servlet-class>org.springframework.ws.transport.http.MessageDispatcherServlet</servlet-class>
<init-param>
<param-name>transformWsdlLocations</param-name>
<param-value>true</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring-ws</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
</web-app>
Then add an empty servlet.xml matching your servlet name ie. spring-ws-servlet.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd">
</beans>
Finally, add a weblogic.xml with the following:
<wls:weblogic-web-app xmlns:wls="http://xmlns.oracle.com/weblogic/weblogic-
web-app" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd
http://xmlns.oracle.com/weblogic/weblogic-web-app
http://xmlns.oracle.com/weblogic/weblogic-web-app/1.4/weblogic-web-app.xsd">
<wls:weblogic-version>12.1.1</wls:weblogic-version>
<wls:context-root>mtaworkflow</wls:context-root>
<wls:container-descriptor>
<wls:prefer-application-packages>
<wls:package-name>org.slf4j.*</wls:package-name>
<wls:package-name>org.springframework.*</wls:package-name>
<wls:package-name>javax.websocket.*</wls:package-name>
<wls:package-name>javax.websocket.server.*</wls:package-name>
</wls:prefer-application-packages>
</wls:container-descriptor>
</wls:weblogic-web-app>
Answered By - Matthew Shaw
Answer Checked By - Pedro (JavaFixing Volunteer)