Issue
https://web.archive.org/web/20110422225659/https://en.wikipedia.org/wiki/Base64#URL_applications
talks about base64Url - Decode
a modified Base64 for URL variant exists, where no padding '=' will be used, and the '+' and '/' characters of standard Base64 are respectively replaced by '-' and '_'
I created the following function:
public static String base64UrlDecode(String input) {
String result = null;
BASE64Decoder decoder = new BASE64Decoder();
try {
result = decoder.decodeBuffer(input.replace('-','+').replace('/','_')).toString();
}
catch (IOException e) {
System.out.println(e.getMessage());
}
return result;
}
it returns a very small set of characters that don't even resemble to the expected results. any ideas?
Solution
With the usage of Base64
from Apache Commons, who can be configured to URL safe, I created the following function:
import org.apache.commons.codec.binary.Base64;
public static String base64UrlDecode(String input) {
String result = null;
Base64 decoder = new Base64(true);
byte[] decodedBytes = decoder.decode(input);
result = new String(decodedBytes);
return result;
}
The constructor Base64(true)
makes the decoding URL-safe.
Answered By - ufk
Answer Checked By - Marie Seifert (JavaFixing Admin)