[FIXED] This appears to create an object from an interface; how does it work?

Issue

interface Int {
   public void show();
}

Int t1 = new Int() {
   public void show() {
      System.out.println("message");
}

to.show();

Solution

You're defining an anonymous class that implements the interface Int, and immediately creating an object of type thatAnonymousClassYouJustMade.

Answered By - Pops
Answer Checked By - Clifford M. (JavaFixing Volunteer)