Issue
Consider the below URL as an example. http://www.test1.example.com
Is there any method by which I can get "example.com" as an output. I know there is a method servletrequest.getServerName()
. It gives me output as test1.example.com
Any help appreciated.
Solution
In HttpServletRequest
, you can get individual parts of the URI using the methods below. You could also use them to reconstruct the URL piece by piece (to help debugging, or other tasks), like this:
// Example: http://myhost:8080/people?lastname=Fox&age=30
String uri = request.getScheme() + "://" + // "http" + "://
request.getServerName() + // "myhost"
":" + request.getServerPort() + // ":" + "8080"
request.getRequestURI() + // "/people"
(request.getQueryString() != null ? "?" +
request.getQueryString() : ""); // "?" + "lastname=Fox&age=30"
So request.getServerName()
is the closest we got to you need.
The "root domain":
For the "root domain", you'll have to work through the String
returned from getServerName()
. This is necessary because the Servlet would have no way of knowing ahead of time what you call "host" or what is just a domain like .com
(it could be a machine called com
in your network - and not just a suffix -, who knows?).
For the pattern you gave (one third+secondlevel+com/net), the following should get what you need:
String domain = request.getServerName().replaceAll(".*\\.(?=.*\\.)", "");
The above will give the following input/outputs:
www.test.com -> test.com
test1.example.com -> example.com
a.b.c.d.e.f.g.com -> g.com
www.com -> www.com
com -> com
Answered By - acdcjunior
Answer Checked By - Mary Flores (JavaFixing Volunteer)