Issue
Why is field nodes returning different size when called from subclass
shouldn't subclasses have access to their super classes fields?
Here is reproducible example:
Manager.java
import java.util.HashMap;
public class Manager {
protected HashMap<Integer,Node> nodes = new HashMap<>();
public HashMap<Integer, Node> getNodes() { return nodes; }
public void addNode(Node node){
nodes.put(nodes.size(),node);
}
public static void main(String[] args) {
Manager manager = new Manager();
manager.addNode(new Node());
System.out.println("(from Manager) manager.nodes.size() = " + manager.nodes.size());
manager.getNodes().get(0).printNodesSize();
}
}
Node.java
public class Node extends Manager {
public void printNodesSize() {
System.out.println("(from Node) manager.nodes.size() = " + super.nodes.size());
}
}
System.out:
(from Manager) manager.nodes.size() = 1
(from instanced Node) manager.nodes.size() = 0
Process finished with exit code 0
Solution
The issue you're having has nothing to see with inheritance. The call:
manager.getNodes()
will return a Map<Integer, Node>
(check your own method definition in the class Manager
) that contains only one element with index 1
(because it's you defining the key as nodes.size()+1
).
Hence when you call manager.getNodes().get(0)
, you get a null
element (the map doesn't contain any element with key 0
).
If you replace .get(0)
by .get(1)
, it will work.
Side note: your design is not very clean. The class Manager
(parent) contains a map of Node
s which is its own child. The child (Node
) is supposed to know its parent (Manager
), but not vice versa.
Edit
The print of super.nodes.size()
is 0 because you're not pointing to the instance of Manager
that you think you're pointing to.
When you do new Node()
(the node that you add to your manager
), you're creating a new Manager()
which has an empty map by default.
So when you call super.nodes.size()
, your super
is not manager
as you think, but the other instance of Manager
that you created when doing new Node()
, to which you never added anything.
Again, I suggest you check my side-note above and re-consider your design.
Answered By - Matteo NNZ
Answer Checked By - Mary Flores (JavaFixing Volunteer)