[FIXED] Switch Statement Issue with Default

Issue

So basically I have this project for school and it contains a switch statement within a while loop.

Lets say I input "1" and its runs the code within case "1". And then it should break after. But the default code always gets run as well.

Here is the case "1" code:

case "1":
    counter = arrayLength();
    if (counter != 20) {
        System.out.print("Student name: ");
        students[array] = sc.nextLine();
        System.out.print("Student mark: ");
        marks[array] = sc.nextByte();
        array++;
        System.out.println("Student added succsessfully.");
    } else {
        System.out.println("You can only add 20 students.");
    }
    break;

Here is the default code:

default:
    System.out.println("Incorrect input. Please try again.");

Here is the output:

1
Student name: Test
Student mark: 50
Student added successfully.
Incorrect input. Please try again.

I am pretty confident that I have my code right, but if there is something I am missing, please tell me how to fix it, thanks.

Solution

public static void main(String[] args) {
        Scanner in = new Scanner(System.in);

        while(true){
            switch(in.nextLine()){
                case "1":
                    System.out.print("Student name: ");
                    String name = in.nextLine();
                    System.out.print("Student mark: ");
                    byte b = in.nextByte();
                    in.nextLine();  //consumes trailing '\n'
                    System.out.println("Student added succsessfully.");
                    break;
                default:
                    System.out.println("Incorrect input. Please try again.");
            }
        }
}

use the in.nextLine() to consume the trailing \n after nextByte(). The explanation is in the link provided in the comment.

Answered By - experiment unit 1998X
Answer Checked By - Mildred Charles (JavaFixing Admin)