[FIXED] In JavaFx, how to remove a specific node from a gridpane with the coordinate of it?

Issue

If I know the specific coordinate of the node I am trying to remove, let's say "col:3, row: 4", how can I remove the node in column 3 and row 4? Is there a built-in method I can use in Java?

Solution

You need to remove node (child) from layout (GridPane)

public Node removeNodeByRowColumnIndex(final int row,final int column,GridPane gridPane) {

ObservableList<Node> childrens = gridPane.getChildren();
for(Node node : childrens) {
    if(node instanceof ImageView && gridPane.getRowIndex(node) == row && gridPane.getColumnIndex(node) == column) {
        ImageView imageView=ImageView(node); // use what you want to remove
        gridPane.getChildren().remove(imageView);
        break;
    }
  } 
   }

Answered By - Menai Ala Eddine - Aladdin
Answer Checked By - Timothy Miller (JavaFixing Admin)