Issue
I am looking for a way to assign/set a filename to a org.springframework.core.io.Resource
object. The object does not have a function available to do this. The getFileName
method in my case returns a null
.
I do not want to create a multipartfile from the Resource object since my Open API spec does not accept it.
Solution
I achieved it like this
//Retrieved the object from S3
S3Object s3Object = amazonS3client.getObject(s3Config.getBucket(), key);
S3ObjectInputStream objectInputStream = s3Object.getObjectContent();
String fileName = s3Object.getObjectMetadata().getUserMetaDataOf("fileName");
//create a ByteArrayResource from the input stream and assigned the fileName
ByteArrayResource fileAsResource = new ByteArrayResource(IOUtils.toByteArray(objectInputStream)) {
@Override
public String getFilename() {
return fileName;
}
@Override
public long contentLength() {
return s3Object.getObjectMetadata().getContentLength();
}
};
Answered By - Amol Kshirsagar
Answer Checked By - Mary Flores (JavaFixing Volunteer)