Issue
In our application almost in every screen we have a button with text 'New', Here is the html source for one of the button:
<button id="defaultOverviewTable:j_id54" class="ui-button ui-widget ui-state-default ui-corner-all ui-button-text-only ui-state-hover" type="submit" name="defaultOverviewTable:j_id54" role="button" aria-disabled="false">
<span class="ui-button-text ui-c">New</span>
</button>
I have tried using the below statement to click on the button:
driver.findElement(By.xpath("//button[[@type, 'submit'] and [text()='New']]")).click();
But this was not working
org.openqa.selenium.InvalidSelectorException: The given selector //button[[@type= 'submit'] and [text()='New']] is either invalid or does not result in a WebElement.
Currently I am using the below code to click on the button:
List<WebElement> allButt = driver.findElements(By.tagName("button"));
for (WebElement w : allButt)
{
if (w.getText().matches("New"))
{
w.click();
break;
}
}
As I have almost 150 buttons in the page. Is there any other way?
Solution
Your xpath syntax is wrong - you don't need the inner set of square brackets - but even if you fix this:
//button[@type, 'submit' and text()='New']
it won't select what you want it to. The problem is that the "New" is not text contained directly in the button element but is inside a child span element. If instead of text()
you just use .
then you can check the whole string value of the element (the concatenation of all descendant text nodes at whatever level)
//button[@type='submit' and contains(., 'New')]
Or check span
instead of text()
:
//button[@type='submit' and span='New']
(submit buttons containing a span whose value is "New")
Answered By - Ian Roberts
Answer Checked By - David Marino (JavaFixing Volunteer)