[FIXED] why is one of these an illegal start of expression and the other one isnt?

Issue

I was trying to declare two methods for a java application, both are written with the correct format, but one is valid and the other is marked as an illegal start of expression, so i was wondering what can i do to fix it?

    /**
     *
     * @param valor
     * @param matriz
     * @return existe
     */
 public static boolean verificaExistencia(int valor, int matriz [][]){//this method is marked as an illegal start of expression altough the format is correct
    boolean existe=false;
    for(int x=0; x<matriz.length;x++){
        if(matriz[x][0]==valor){
            existe=true;
            break;
        }
    }
    return existe;
}

    /**
     * 
     * @param valor
     * @param array
     * @return conta
     */    
    public static int cuantasVecesExiste(int valor, int array[]){//this method uses the same format as the one above, but is considered valid, what is the issue with the first one?
    int conta=0;
    for(int x=0;x<array.length;x++){
        if(array[x]==valor)
            conta++;
    }
    return conta;
}
}

Solution

Try

public static boolean verificaExistencia(int valor, int matriz[][]) {
    for (int x = 0; x < matriz.length; x++) {
        if (matriz[x][0] == valor) {
            return true;
        }
    }
    return false;
}

Why do you only check the first column in the matrix? If you want to iterate the full matrix you could do somthing like:

 public static boolean verificaExistencia(int valor, int matriz[][]) {
    for (int row = 0; row < matriz.length; row++) {
        for (int col = 0; col < matriz[row].length; col++) {
            if (matriz[row][col] == valor) {
                return true;
            }
        }
    }
    return false;
}

Answered By - corn_not_slapped
Answer Checked By - Katrina (JavaFixing Volunteer)