[FIXED] Java Wrong Input For Vector Loop Until Correct

Issue

I need to place in a selected by User input quantity, numbers that are only in between 1 and 60, values less than 1 and more than 60 should be invalid... And asked for a new input.

Thing is, I don't know how to repeat the question and replace in the vector's square where the wrong value was inserted, to the correct one.

Ex: It keeps asking for the values, ignoring in regards of it being wrong and showing it later... Such as vector[6], the values in the end shows like: [45, 34, 23, 22, 11, 99] or [45, 55, 34, 99, 99, 99]

My task: Develop an algorithm that records bets. The player can perform bets of 6 to 15 numbers, between 1 and 60. The algorithm must then request that the inform user:

1. the quantity of numbers in your bet;
2. receiving bets (between 1 and 60);
3. show the bet placed in order and;
4. show the amount to be charged for it (following a table I was given).

My attempt:

Scanner teclado = new Scanner(System.in);
System.out.println("How many bets from 6 to 15?");
int qntd = teclado.nextInt();
int c;
int i = 0;
if ((qntd < 6) || (qntd > 15)){
    System.out.println("Only 6 to 15 values.");
} else {
    int[] bets = new int [qntd]; 
    for (c=0; c<=bets.length-1; c++ ){
        i++;
        System.out.println("Choose a number ");
        bets[c] = teclado.nextInt();               
        if ((bets[c] < 1) || (bets[c]>60)) {
            System.out.println("Only 1 to 60 values.");
        }    
    }    
    Arrays.sort(bets);
    System.out.print("Realized bets [");
    for (int valor: bets){
        System.out.print( " " + valor  );                         
    }
    System.out.println(" ]");
    System.out.println(" ]");
    String pr = null;   
    int vlr = qntd;                     
    switch (vlr){
        case 6 : 
            pr = "4,50.";
            break;
        case 7 : 
            pr = "31,50.";
            break;
        case 8 : 
            pr = "126,00.";
            break;
        case 9 : 
            pr = "378,00.";
            break;
         case 10 : 
            pr = "945,00.";
            break;
        case 11 : 
            pr = "2.079,00.";
            break;
        case 12 : 
            pr = "4.158,00.";
            break;
        case 13:
            pr = "7.722,00,";
            break;
        case 14 :
            pr = "13.513,50.";
            break;
        case 15 : 
            pr = "22.522,50.";                                 
    }
    System.out.println("Bets value is R$ " + pr);
}
    

Solution

You don't have to insert an invalid input into the array.

int c=0;
while(c<bets.length){
    System.out.println("Choose a number ");
    int input = teclado.nextInt();
    if ((input < 1) || (input > 60)) {
        System.out.println("Only 1 to 60 values.");
        continue;
    }
    bets[c]=input;  
    c++; 
}

For an invalid input the loop would continue without adding the input to the array. Also c would be incremented only for valid input.

Answered By - Gautham M
Answer Checked By - Mildred Charles (JavaFixing Admin)