[FIXED] how to create two jars from one Maven project but with different resources files

Issue

I have a single maven project that has multiple folders in src/main/resources, I want to generate two Jars, one include src/main/resources/folder1/all properties and the other include src/main/resources/folder2/all properties.

Is their a way to achive this ? If not, what is the simplest way to achive my goal?

Solution

If I understood your problem correctly then you can use "Maven Assembly plugin" and "The Assembly Descriptor" in the following way: first of all, you can not use a profile if you want to build 2 jar files simultaneously. So, my suggestion is to exclude your config files from your jar then use Maven Assembly plugin to create a different zip file with these folders.

for example, in your case you should have 2 file descriptors like the following:

               <plugin>
                <artifactId>maven-assembly-plugin</artifactId>
                <executions>
                    <execution>
                        <id>folder1</id>
                        <phase>package</phase>
                        <goals>
                            <goal>single</goal>
                        </goals>
                        <configuration>
                            <descriptors>
                                <descriptor>src/main/java/descriptors/folder1.xml</descriptor>
                            </descriptors>
                        </configuration>
                    </execution>
                </executions>
            </plugin>

and folder1.xml contains:

<assembly>
    <id>folder1</id>
    <formats>
        <format>zip</format>
    </formats>
    <files>
        <file>
            <source>
                target/${project.artifactId}-${project.version}-yourJar.jar
            </source>
            <outputDirectory>/</outputDirectory>
        </file>
    </files>
    <fileSets>
        <fileSet>
            <directory>${project.basedir}/src/main/resources/folder1</directory>
            <includes>
                <include>*</include>
            </includes>
            <outputDirectory>/config</outputDirectory>
        </fileSet>
    </fileSets>
</assembly>

for "folder2" you can do it in the same way.

also for exclude some config files from the jar you can use this plugin:

<plugin>
  <groupId>org.apache.maven.plugins</groupId>
  <artifactId>maven-jar-plugin</artifactId>
  <version>2.3</version>
  <configuration>
    <excludes>
      <exclude>**/*.properties</exclude>
    </excludes>                    
    <archive>
      <manifest>
        <addClasspath>true</addClasspath>
        <classpathPrefix>lib/</classpathPrefix>
        <mainClass>package.path.to.your.main.class.MainClass</mainClass>
      </manifest>
      <manifestEntries>
        <Class-Path>conf/</Class-Path>
      </manifestEntries>
    </archive>
  </configuration>
</plugin>

Using maven-resources-plugin as follows:

  <plugin>
      <groupId>org.apache.maven.plugins</groupId>
      <artifactId>maven-resources-plugin</artifactId>
      <version>2.3</version>
      <executions>
        <execution>
          <id>copy-resources</id>
          <phase>install</phase>
          <goals>
            <goal>copy-resources</goal>
          </goals>
          <configuration>
            <outputDirectory>${basedir}/target/conf</outputDirectory>
            <resources>
              <resource>
                <directory>src/main/resources</directory>
                <includes>
                  <include>**/*.properties</include>
                </includes>
              </resource>
            </resources>
          </configuration>
        </execution>
      </executions>
    </plugin>

Answered By - Saman Salehi
Answer Checked By - Gilberto Lyons (JavaFixing Admin)