Issue
Below is the web.xml of my project.
<web-app> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <context-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/config/applicationContext-service.xml /WEB-INF/config/applicationContext-dao.xml </param-value> </context-param> <servlet> <servlet-name>dispatcher</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/config/servlet-context.xml ***/WEB-INF/config/applicationContext.xml*** </param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> </web-app>
If I want to convert my project into java based configuration, I know that webapplicationcontext can be configured by using AbstractAnnotationConfigDispatcherServletInitializer or webapplicationinitializer. But how can i configure context-param using java configuration ?
Solution
What you can do is you can use servlet context to store the param name and param values by using setattribute and getattribute methods of servlet context by which you can acess them any where throughout your application and check this for more clarification.
https://www.javatpoint.com/servletcontext
Answered By - gagangaur
Answer Checked By - Cary Denson (JavaFixing Admin)
