[FIXED] How do I get the file path from the content URI for video files?

Issue

I want to attach images or video files from the Android storage. When I select a video from the gallery, it returns the content uri path.

How do I get the file path with extension from the content URI?

---

I tried following code, but it returns null in lollipop:

void pickVideo() {
    Intent videoIntent = new Intent(Intent.ACTION_GET_CONTENT);
    videoIntent.setType("video/*");
    startActivityForResult(videoIntent, PICK_VIDEO_FILE);
}


@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    try {
        if (resultCode != Activity.RESULT_OK)
            return;

        switch (requestCode) {
            case PICK_VIDEO_FILE:
                Uri videoUri = data.getData();
                String path = getRealPathFromURI(getContext(), videoUri);
                Log.d("Video uri path", "path" + path);
                if (mChooseFileDialogListener != null) {
                    mChooseFileDialogListener.onVideoClick(videoUri, HealthRecordViewModel.FILE_TYPE_VIDEO);
                }
                break;
        }
    }
}


public String getRealPathFromURI(Context context, Uri contentUri) {
    Cursor cursor = null;
    try {
        String[] proj = { MediaStore.Video.Media.DATA };
        cursor = context.getContentResolver().query(contentUri,  proj, null, null, null);
        int column_index = cursor.getColumnIndexOrThrow(MediaStore.Video.Media.DATA);
        cursor.moveToFirst();
        return cursor.getString(column_index);
    } finally {
        if (cursor != null) {
            cursor.close();
        }
    }
}

Solution

How to get the file path with extension?

You don't. There is no requirement that the user select a piece of content that is saved as a file in a place that you have read access to. And there is no requirement that a ContentProvider offer some means of translating a Uri to a file path.

Use ContentResolver and openInputStream() to read in the content identified by the Uri.

Answered By - CommonsWare
Answer Checked By - David Marino (JavaFixing Volunteer)