[FIXED] stringRounds is Looping, Rejecting Valid Value

Issue

The loop is working when I enter invalid values, but it still shows the same message when I enter a Valid value. Please help.

public class RockPaperScissors {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        Random rnd = new Random();
    
        String stringRounds = " ";
    
        System.out.println("Welcome to Rock, Paper Scissors!");
        System.out.println("Let's begin with the number of rounds you would like to play: " );
        stringRounds = sc.nextLine();  
        
        int rounds = Integer.parseInt(stringRounds);
        
        while (rounds < 1 || rounds > 10) {
            System.out.println(stringRounds + (" is out of my range. Please try again."));
            stringRounds = sc.nextLine();
        }
        System.out.println(stringRounds +(" sounds good to me. Let's Get Started!!"));
    }
}

Solution

Because you don't update the value of rounds in the while loop.

public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        Random rnd = new Random();
    
        String stringRounds = " ";
    
        System.out.println("Welcome to Rock, Paper Scissors!");
        System.out.println("Let's begin with the number of rounds you would like to play: " );
        stringRounds = sc.nextLine();  
        
        int rounds = Integer.parseInt(stringRounds);
        
        while (rounds < 1 || rounds > 10) {
            System.out.println(stringRounds + (" is out of my range. Please try again."));
            stringRounds = sc.nextLine();
            rounds=  Integer.parseInt(stringRounds);//add this row
        }
        System.out.println(stringRounds +(" sounds good to me. Let's Get Started!!"));
    }

Answered By - Zinedine Benkhider
Answer Checked By - Willingham (JavaFixing Volunteer)