[FIXED] How to search string LIKE 'something%' with Java Spring Framework?

Issue

I've got a MySQL table with Foos. Each Foo has a numeric non-unique code and a name. Now I need to find if any Foo with one of certain codes happens to have a name that starts with a given string. In normal SQL this would be trivial:

select * from FOO where CODE in (2,3,5) and NAME like 'bar%';

But how would I properly do this in Spring now? Without the need for the 'like' operator I'd do it like this:

public List<Foo> getByName(List<Integer> codes, String namePart) {
    String sql = "select * from FOO where CODE in (:codes) and NAME=:name"
    Map<String,Object> params = new HashMap<String,Object>();
    params.put("codes", codes);
    params.put("name", namePart);
    return getSimpleJdbcTemplate().query(sql, new FooRowMapper(), params);
}

However, with 'like' nothing seems to work: NAME like :name%, NAME like ':name%', or NAME like ?% when using the placeholders instead of named parameters.

I could be brutal and enter it as

String sql = "select * from FOO where CODE in (:codes) and NAME like '"+namePart+"%'";` 

but obviously it would be more than nice if Spring would sanitize the input parameters properly etc, you know...

You'd think Spring would support this somehow but I cannot figure it out.

Solution

Wait, of course I had to "try one more final thing" before calling it a day, and lo and behold, all my unit tests suddenly pass:

public List<Foo> getByName(List<Integer> codes, String namePart) {
    String sql = "select * from FOO where CODE in (:codes) and NAME like :name"
    Map<String,Object> params = new HashMap<String,Object>();
    params.put("codes", codes);
    params.put("name", namePart+"%");
    return getSimpleJdbcTemplate().query(sql, new FooRowMapper(), params);
}

I didn't think of entering the "%" in the parameter, I was certain Spring would automatically escape it. I wonder if I'm doing it right?

Answered By - ZeroOne