Issue
I am trying to build a specification which takes as an input Set UUID fooIds and long olderThanInMillis.
My method should return a List of Result. The Result has a fooId as a field (not id). In the table, there may be many objects with identical fooId. However I wish to get only 1 Result per fooId.
My current specification looks like this:
private Specification<Result> buildSpec(Set<UUID> fooIds, long olderThanMilis)
{
Specification<Result> idSpec = (root, query, builder) -> builder.or(builder.in(root.get("fooId")).value(clientPoses));
Specification<Result> olderThanSpec = (root, query, builder) -> builder.lessThanOrEqualTo(root.get("created"), olderThanMilis);
return idSpec.and(olderThanSpec);
}
I am trying to pack something on top of what I have, but nothing seems to work. Possible workaround is of course not to load from DB a List, but rather load it one by one per fooId and olderThanMillis with limit 1... In case of loading it one by one, is that a bad practice or not? Any advice, please? Thank you...
Solution
Usually, this is handled by sorting by something unique and using setMaxResults(1)
, but I don't know how Spring Data supports this.
Answered By - Christian Beikov