[FIXED] Java - Create grid of buttons with array, all with unique ID

Issue

I am making a game-board which requires a grid of buttons. I have a method where I can put in the width and height of the board and draw it like this:

for (int i = 0; i < gameBoardWidth; i++) {
            for (int j = 0; j < gameBoardHeight; j++) {
                gameLayout.add(tiles[j], j, i);

            }
        }

The code above works perfectly fine but the problem is, I have an array of buttons. the size of the array is equal to the width * height, Each button within that array needs to have a unique ID incremented from 1 to n. Previously I made the board with this method

for(int i = 0; i < gameBoardDimension; i++) {
            tiles[i] = new Button("");
            tiles[i].setMinSize(gameButtonWidth, gameButtonHeight);
            tiles[i].setId(Integer.toString(i));

            Button btn = tiles[i];
            btn.setOnAction(e -> {
                turn = 1;
                int ID = Integer.parseInt(btn.getId());
                setMove(ID, turn, btn);
                setAIMove();
            });
        }

But with the method above it is impossible to show them in a grid. How can I show the buttons in a grid so every button in the array has an ID of 1 to n with n being the size of the array?

Solution

Create an id as row (i) times width plus column (j) (plus 1 to start from 1 instead of 0) in the loop

for (int i = 0; i < gameBoardWidth; i++) {
    for (int j = 0; j < gameBoardHeight; j++) {
         Button b = new Button("");
         //... other stuff for button
         int id = i * gameBoardWidth + j + 1;
         b.setId(Integer.toString(id));

         //...
        }
    }

Answered By - Joakim Danielson