[FIXED] i have a problem with lua eclipse ide some one can help me?

Issue

you can see the problem here

I started programming in lua and I wanted to make a simple program. the problem I’m experiencing is that if I enter if functions within the code the program won’t start and auto ends at startup

as you can see from image the compiler said "terminated"

update: now the code looks like this

local function main()
print("insert four binary number for color encryption")
a,b,c,d = io.read("*n","*n","*n","*n")
a=n
b=n
c=n
d=n
end
main()
if(a == 1){
print(white)        
} 
then
print(black)
end

i moved the if under the main() at the end

now the console gives nil follow by

Exception in thread "main" com.naef.jnlua.LuaRuntimeException: ...t-win32.win32.x86_64\workspace\luabello\src\main.lua:10: attempt to call a boolean value
    at com.naef.jnlua.LuaState.lua_pcall(Native Method)
    at com.naef.jnlua.LuaState.call(LuaState.java:555)
    at org.eclipse.ldt.support.lua51.internal.interpreter.JNLua51Launcher.run(JNLua51Launcher.java:128)
    at org.eclipse.ldt.support.lua51.internal.interpreter.JNLua51Launcher.main(JNLua51Launcher.java:143)

update 2: now the code looks like this

local function main()
print("insert four binary number for color encryption")
a,b,c,d = io.read("*n","*n","*n","*n")

end
main()
a=n
b=n
c=n
d=n
if(a <= 1){
print(white)        
} 
then
else
print(black)
end

it gave me another error

Exception in thread "main" com.naef.jnlua.LuaRuntimeException: ...t-win32.win32.x86_64\workspace\luabello\src\main.lua:11: attempt to compare nil with number
    at com.naef.jnlua.LuaState.lua_pcall(Native Method)
    at com.naef.jnlua.LuaState.call(LuaState.java:555)
    at org.eclipse.ldt.support.lua51.internal.interpreter.JNLua51Launcher.run(JNLua51Launcher.java:128)
    at org.eclipse.ldt.support.lua51.internal.interpreter.JNLua51Launcher.main(JNLua51Launcher.java:143)

Solution

your if condition is probably not what you expect it to be,

if(a == 1){
print(white)        
} 

this will attempt to call the result of a == 1 and pass for the first param {print(white)} then evaluate if that is true, but you will get an error as you can not call the result of a == 1 as it is a boolean value.

I believe you meant:

if(a == 1) then
    print(white)        
else
    print(black)
end

---

Also you are setting a,b,c,d twice,

1. to the result of io.read("*n","*n","*n","*n")
2. to n which is not defined so the values are set to nil

Answered By - Nifim