[FIXED] How to create containerized Spring Boot App on Raspberry Pi 4?

Issue

What am I wanting to do?

I want to convert to run my containerized of Spring-Boot's app which is can run on amd64 systems, on Raspberry Pi 4's Docker. How can I fix the my problem?

What's the running OS on Raspberry Pi?

I've installed Ubuntu Server 20.04.2 LTS for arm64 architectures using via Raspberry Pi Imager v1.6.1 on Raspberry Pi 4.

---

What are the steps I have done to fix the problem?(problem is still continue)

In default version does not work on my Raspberry Pi. Thus, I've tried some couple of things at below.

I changed row of "FROM" from openjdk:15-jdk-slim to arm64v8/openjdk:17 at my dockerfile as you can see:

FROM arm64v8/openjdk:17
COPY . /projects/red-dir
WORKDIR /projects/red-dir
ARG JAR_FILE=target/*.jar
COPY ${JAR_FILE} /projects/red-dir/my_red_app.jar
ENTRYPOINT ["java","-jar","/projects/red-dir/my_red_app.jar"]

Afterwards, I've built and pushed my app using with Maven and Docker:

$ ./mvnw clean package -Dmaven.test.skip=true && java -jar target/my_red_app.jar
$ docker build -t user/my_red_app:v1.0.0 .

Then, My app's depend on a MongoDB, so I changed this image from mongo to arm64v8/mongo on docker-compose.yml as you can see at below:

version: "3"
services:
    mongodb:
        container_name: mongodb
        image: arm64v8/mongo
        restart: always
        ports:
            - 27017:27017
        environment:
            MONGO_INITDB_ROOT_USERNAME: admin
            MONGO_INITDB_ROOT_PASSWORD: 12345
        networks:
            - shared-net
    colour_app:
        container_name: my_red_app
        image: user/my_red_app
        restart: always
        ports:
            - 7070:7070
        depends_on:
            - mongodb
        networks:
            - shared-net
networks:
    shared-net:
        driver: bridge

---

Things that work and things that don't work

MongoDB is running. I can reach using via MongoDBCompass, but my Spring-Boot app doesn't work. In docker-compose up command, I've encountered an output like this:

...
...
colour_app    | standard_init_linux.go:219: exec user process caused: exec format error
colour_app    | standard_init_linux.go:219: exec user process caused: exec format error
colour_app    | standard_init_linux.go:219: exec user process caused: exec format error
colour_app    | standard_init_linux.go:219: exec user process caused: exec format error

Let me know what things I didn't catch. Thank you for reading.

Solution

I've solved my problem and tried to create simple guide for ones who are encountered this problem.

BUILD FOR OTHER OS (multi-architecture / buildx command)

1. Turn On "experimental" feature's on Docker Settings.
   • For Linux OS:
     1. sudo nano /etc/docker/daemon.json
     2. Add below content to it:

        {
          "experimental": true
        }
        

   • For Win10 OS / MAC OS:
     1. Open Docker Desktop application.
     2. Go to Settings.
     3. Select Docker Engine Tab on the left-side.
     4. Find "experimental": false.
     5. Change it to "experimental": true.
2. Restart Docker.
3. Create multi-architecture os. (Important: The image you are using should contain the OS you want to create it)

   • Creating a just SINGLE OS :

     1. You can use load or push commands.
        • --load means that docker saves it to local disk:

          docker buildx build --load --platform linux/arm64 -t <dockerhub_username>/<repository_name>:<tag_name> .
          

        • --push means that docker doesn't save it to local disk but save it to cloud (docker hub):

          docker buildx build --push --platform linux/arm64 -t <dockerhub_username>/<repository_name>:<tag_name> .
          

        • --load and --push can not be set together.

   • Creating a MANY OS :

     2. You can just use push command with many OS.

        • --push means that docker doesn't save it to local disk but save it to cloud (docker hub):

          docker buildx build --push --platform linux/amd64,linux/arm64,linux/ppc64le -t <dockerhub_username>/<repository_name>:<tag_name> .
          

Answered By - E G