Issue
I have the following code in one of my controllers:
@Controller
@RequestMapping("/preference")
public class PreferenceController {
@RequestMapping(method = RequestMethod.GET, produces = "text/html")
public String preference() {
return "preference";
}
}
I am simply trying to test it using Spring MVC test as follows:
@ContextConfiguration
@WebAppConfiguration
@RunWith(SpringJUnit4ClassRunner.class)
public class PreferenceControllerTest {
@Autowired
private WebApplicationContext ctx;
private MockMvc mockMvc;
@Before
public void setup() {
mockMvc = webAppContextSetup(ctx).build();
}
@Test
public void circularViewPathIssue() throws Exception {
mockMvc.perform(get("/preference"))
.andDo(print());
}
}
I am getting the following exception:
Circular view path [preference]: would dispatch back to the current handler URL [/preference] again. Check your ViewResolver setup! (Hint: This may be the result of an unspecified view, due to default view name generation.)
What I find strange is that it works fine when I load the "full" context configuration that includes the template and view resolvers as shown below:
<bean class="org.thymeleaf.templateresolver.ServletContextTemplateResolver" id="webTemplateResolver">
<property name="prefix" value="WEB-INF/web-templates/" />
<property name="suffix" value=".html" />
<property name="templateMode" value="HTML5" />
<property name="characterEncoding" value="UTF-8" />
<property name="order" value="2" />
<property name="cacheable" value="false" />
</bean>
I am well aware that the prefix added by the template resolver ensures that there is not "circular view path" when the app uses this template resolver.
But then how I am supposed to test my app using Spring MVC test?
Solution
This has nothing to do with Spring MVC testing.
When you don't declare a ViewResolver
, Spring registers a default InternalResourceViewResolver
which creates instances of JstlView
for rendering the View
.
The JstlView
class extends InternalResourceView
which is
Wrapper for a JSP or other resource within the same web application. Exposes model objects as request attributes and forwards the request to the specified resource URL using a javax.servlet.RequestDispatcher.
A URL for this view is supposed to specify a resource within the web application, suitable for RequestDispatcher's forward or include method.
Emphasis mine. In other words, the view, before rendering, will try to get a RequestDispatcher
to which to forward()
. Before doing this it checks the following
if (path.startsWith("/") ? uri.equals(path) : uri.equals(StringUtils.applyRelativePath(uri, path))) {
throw new ServletException("Circular view path [" + path + "]: would dispatch back " +
"to the current handler URL [" + uri + "] again. Check your ViewResolver setup! " +
"(Hint: This may be the result of an unspecified view, due to default view name generation.)");
}
where path
is the view name, what you returned from the @Controller
. In this example, that is preference
. The variable uri
holds the uri of the request being handled, which is /context/preference
.
The code above realizes that if you were to forward to /context/preference
, the same servlet (since the same handled the previous) would handle the request and you would go into an endless loop.
When you declare a ThymeleafViewResolver
and a ServletContextTemplateResolver
with a specific prefix
and suffix
, it builds the View
differently, giving it a path like
WEB-INF/web-templates/preference.html
ThymeleafView
instances locate the file relative to the ServletContext
path by using a
ServletContextResourceResolver
templateInputStream = resourceResolver.getResourceAsStream(templateProcessingParameters, resourceName);`
which eventually
return servletContext.getResourceAsStream(resourceName);
This gets a resource that is relative to the ServletContext
path. It can then use the TemplateEngine
to generate the HTML. There's no way an endless loop can happen here.
Answered By - Sotirios Delimanolis